2808=6w+2w^2

Solution for 2808=6w+2w^2 equation:

2808=6w+2w^2

We move all terms to the left:

2808-(6w+2w^2)=0

We get rid of parentheses

-2w^2-6w+2808=0

a = -2; b = -6; c = +2808;
Δ = b2-4ac
Δ = -62-4·(-2)·2808
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-150}{2*-2}=\frac{-144}{-4}
=+36
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+150}{2*-2}=\frac{156}{-4}
=-39
$